Claude vs ChatGPT for math

Every limit is published. Paid plans also have a monthly fair-use limit on AI cost: Pro $7.50, Max $20, Ultra $42, Studio $85. Using every message on your plan at typical sizes stays under it; very large messages and heavy research use it faster. Every limit, explained.

Math: Claude Haiku 4.5 passed 5 of 5 and GPT-6 Sol 5 of 5. Their median waits were close, 2.2 s against 2.2 s. Claude Haiku 4.5 cost 1.2× less, $0.0077 against $0.0090 for the 5 replies. Claude Haiku 4.5's replies ran 236% longer, in tokens of reply, thinking not counted.

1. 1. A discount, then sales tax

   Everyday. Claude: 5 of 5 models passed, Claude Haiku 4.5 the cheapest at $0.0007 · GPT: 3 of 3 models passed, GPT-6 Luna the cheapest at $0.0001. The prompt in full.

   Claude Haiku 4.5 and GPT-6 Sol both passed this one. Claude Haiku 4.5 answered sooner (1.1 s to 1.7 s), and Claude Haiku 4.5's reply cost less ($0.0007 to $0.0013); Claude Haiku 4.5 wrote 63 tokens of reply, GPT-6 Sol 45.

   • Claude Haiku 4.5

     Passed: Final answer 66: right.

     **Working:**
     
     1. Original price: $80
     2. Apply 25% discount: $80 × 0.75 = $60
     3. Add 10% sales tax: $60 × 1.10 = $66
     
     Final answer: $66

     429 tokens in, 63 out · 1.1 s · $0.0007 · 1 message on Pro · answered by anthropic/claude-haiku-4.5 via Amazon Bedrock · September 27, 2026

   • GPT-6 Sol

     Passed: Final answer 66: right.

     25% off $80 gives $80 × 0.75 = $60.  
     Adding 10% sales tax gives $60 × 1.10 = $66.
     
     Final answer: $66

     400 tokens in, 45 out · 1.7 s · $0.0013 · 1 message on Pro · answered by openai/gpt-6-sol via OpenAI · September 27, 2026

2. 2. Pens at 3 for $4

   Everyday. Claude: 5 of 5 models passed, Claude Haiku 4.5 the cheapest at $0.0014 · GPT: 2 of 3 models passed, GPT-6 Sol the cheapest at $0.0024. The prompt in full.

   Claude Haiku 4.5 and GPT-6 Sol both passed this one. Claude Haiku 4.5 answered sooner (2.2 s to 3.3 s), and Claude Haiku 4.5's reply cost less ($0.0014 to $0.0024); Claude Haiku 4.5 wrote 199 tokens of reply, GPT-6 Sol 56.

   • Claude Haiku 4.5

     Passed: Final answer Buy 3 packs of 3 pens and 1 single pen for 13.50: right.

     # Pen Purchase Problem
     
     **Option 1: Buy 3-packs only**
     - 10 pens ÷ 3 = 3 packs with 1 pen left over
     - 3 packs × $4 = $12
     - 1 single pen × $1.50 = $1.50
     - Total: $13.50
     
     **Option 2: Buy all single pens**
     - 10 pens × $1.50 = $15.00
     
     **Option 3: Buy 3 packs + adjust**
     - Same as Option 1: $13.50
     
     The cheapest way is to buy three 3-packs ($12) and one single pen ($1.50).
     
     Final answer: Buy 3 packs of 3 pens and 1 single pen for $13.50

     434 tokens in, 199 out · 2.2 s · $0.0014 · 1 message on Pro · answered by anthropic/claude-haiku-4.5 via Amazon Bedrock · September 27, 2026

   • GPT-6 Sol

     Passed: Final answer 13.50: right.

     Three groups of 3 pens cost \(3 \times \$4 = \$12\). One single pen costs \$1.50, bringing the total to \$13.50. Using fewer groups would cost more.
     
     Final answer: $13.50

     402 tokens in, 164 out (108 of them reasoning) · 3.3 s · $0.0024 · 1 message on Pro · answered by openai/gpt-6-sol via OpenAI · September 27, 2026

3. 3. Compound interest over three years

   Everyday. Claude: 5 of 5 models passed, Claude Haiku 4.5 the cheapest at $0.0013 · GPT: 3 of 3 models passed, GPT-6 Luna the cheapest at $0.0001. The prompt in full.

   Claude Haiku 4.5 and GPT-6 Sol both passed this one. GPT-6 Sol answered sooner (1.4 s to 3.5 s), and cost about the same; Claude Haiku 4.5 wrote 173 tokens of reply, GPT-6 Sol 62.

   • Claude Haiku 4.5

     Passed: Final answer 315.25: right.

     I'll calculate the compound interest for you.
     
     **Formula:** A = P(1 + r)^n
     
     Where:
     - P = Principal = $2,000
     - r = Annual interest rate = 0.05
     - n = Number of years = 3
     
     **Calculation:**
     - Year 1: $2,000 × 1.05 = $2,100.00
     - Year 2: $2,100 × 1.05 = $2,205.00
     - Year 3: $2,205 × 1.05 = $2,315.25
     
     **Interest earned:**
     $2,315.25 - $2,000.00 = $315.25
     
     Final answer: $315.25

     430 tokens in, 173 out · 3.5 s · $0.0013 · 1 message on Pro · answered by anthropic/claude-haiku-4.5 via Amazon Bedrock · September 27, 2026

   • GPT-6 Sol

     Passed: Final answer 315.25: right.

     After 3 years, the balance is \(2000(1.05)^3=\$2,315.25\). Subtracting the original deposit gives \(2315.25-2000=\$315.25\) in interest.
     
     Final answer: $315.25

     402 tokens in, 62 out · 1.4 s · $0.0014 · 1 message on Pro · answered by openai/gpt-6-sol via OpenAI · September 27, 2026

4. 4. Four-digit numbers whose digits sum to 9

   Hard. Claude: 5 of 5 models passed, Claude Haiku 4.5 the cheapest at $0.0024 · GPT: 3 of 3 models passed, GPT-6 Luna the cheapest at $0.0001. The prompt in full.

   Claude Haiku 4.5 and GPT-6 Sol both passed this one. GPT-6 Sol answered sooner (2.5 s to 2.9 s), and GPT-6 Sol's reply cost less ($0.0019 to $0.0024); Claude Haiku 4.5 wrote 404 tokens of reply, GPT-6 Sol 78.

   • Claude Haiku 4.5

     Passed: Final answer 165: right.

     I need to find four-digit positive integers where the digits sum to 9.
     
     A four-digit positive integer has the form $\overline{abcd}$ where:
     - $a \in \{1,2,...,9\}$ (first digit can't be 0)
     - $b,c,d \in \{0,1,...,9\}$
     - $a + b + c + d = 9$
     
     **Method: Change of variables**
     
     Let $a' = a - 1$, so $a' \in \{0,1,...,8\}$.
     
     Then: $a' + 1 + b + c + d = 9$
     
     This gives: $a' + b + c + d = 8$
     
     Now I need to count non-negative integer solutions where:
     - $a' \in \{0,1,...,8\}$
     - $b,c,d \in \{0,1,...,9\}$
     - $a' + b + c + d = 8$
     
     Since the sum is only 8, each variable is automatically ≤ 8 (and thus $a' \leq 8$ and $b,c,d \leq 9$ are automatically satisfied).
     
     This is a standard stars and bars problem: distribute 8 identical objects into 4 distinct bins with no restrictions.
     
     The number of solutions is:
     $$\binom{8 + 4 - 1}{4 - 1} = \binom{11}{3} = \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = \frac{990}{6} = 165$$
     
     Final answer: 165

     404 tokens in, 404 out · 2.9 s · $0.0024 · 1 message on Pro · answered by anthropic/claude-haiku-4.5 via Amazon Bedrock · September 27, 2026

   • GPT-6 Sol

     Passed: Final answer 165: right.

     Subtract 1 from the thousands digit. The four digits then become nonnegative integers that sum to 8. By stars and bars, the number of solutions is \(\binom{8+4-1}{4-1}=\binom{11}{3}=165\). Every solution gives a valid four-digit integer.
     
     Final answer: 165

     378 tokens in, 117 out (39 of them reasoning) · 2.5 s · $0.0019 · 1 message on Pro · answered by openai/gpt-6-sol via OpenAI · September 27, 2026

5. 5. The highest of three dice is a 5

   Hard. Claude: 5 of 5 models passed, Claude Haiku 4.5 the cheapest at $0.0018 · GPT: 3 of 3 models passed, GPT-6 Luna the cheapest at $0.0001. The prompt in full.

   Claude Haiku 4.5 and GPT-6 Sol both passed this one. They took about as long (Claude Haiku 4.5 2.2 s, GPT-6 Sol 2.2 s), and Claude Haiku 4.5's reply cost less ($0.0018 to $0.0020); Claude Haiku 4.5 wrote 276 tokens of reply, GPT-6 Sol 91.

   • Claude Haiku 4.5

     Passed: Final answer 61/216: right.

     I need to find the probability that the maximum of three dice is exactly 5.
     
     **Working:**
     
     For the maximum to be exactly 5:
     - At least one die shows 5
     - No die shows 6
     
     **Count favorable outcomes:**
     - All three dice must show values from {1, 2, 3, 4, 5}
     - At least one die must show 5
     
     Using complementary counting:
     - Total ways to roll three dice with values in {1,2,3,4,5}: 5³ = 125
     - Ways with no 5 (all from {1,2,3,4}): 4³ = 64
     - Ways with at least one 5: 125 - 64 = 61
     
     **Total possible outcomes:** 6³ = 216
     
     **Probability:** 61/216
     
     Let me verify this is in lowest terms by checking if 61 and 216 share factors:
     - 61 is prime
     - 216 = 2³ × 3³
     - Since 61 is prime and doesn't equal 2 or 3, gcd(61, 216) = 1
     
     Final answer: 61/216

     420 tokens in, 276 out · 2.2 s · $0.0018 · 1 message on Pro · answered by anthropic/claude-haiku-4.5 via Amazon Bedrock · September 27, 2026

   • GPT-6 Sol

     Passed: Final answer 61/216: right.

     For the highest number to be exactly 5, all three dice must show 5 or less, but not all can show 4 or less.
     
     \[
     P(\text{highest is }5)=\left(\frac56\right)^3-\left(\frac46\right)^3
     =\frac{125-64}{216}=\frac{61}{216}.
     \]
     
     Final answer: 61/216

     393 tokens in, 122 out (31 of them reasoning) · 2.2 s · $0.0020 · 1 message on Pro · answered by openai/gpt-6-sol via OpenAI · September 27, 2026

• Claude Fable 5.1 vs GPT-6 Astra: 5 of 5 each; GPT-6 Astra answered 1.8× sooner at the median and cost 1.4× less. Claude Fable 5.1 vs GPT-6 Astra, on every job.

• Claude Fable 5.1 vs GPT-6 Sol: 5 of 5 each; GPT-6 Sol answered 2.1× sooner at the median and cost 6.4× less.

• Claude Fable 5.1 vs GPT-6 Luna: Claude Fable 5.1 5 of 5, GPT-6 Luna 4; GPT-6 Luna answered 2.1× sooner at the median and cost 118.2× less.

• Claude Opus 5.5 vs GPT-6 Astra: 5 of 5 each; GPT-6 Astra answered 1.5× sooner at the median and Claude Opus 5.5 cost 1.4× less. Claude Opus 5.5 vs GPT-6 Astra, on every job.

• Claude Opus 5.5 vs GPT-6 Sol: 5 of 5 each; GPT-6 Sol answered 1.8× sooner at the median and cost 3.3× less. Claude Opus 5.5 vs GPT-6 Sol, on every job.

• Claude Opus 5.5 vs GPT-6 Luna: Claude Opus 5.5 5 of 5, GPT-6 Luna 4; GPT-6 Luna answered 1.8× sooner at the median and cost 60.5× less.

• Claude Sonnet 5.5 vs GPT-6 Astra: 5 of 5 each; Claude Sonnet 5.5 answered 1.6× sooner at the median and cost 3.5× less.

• Claude Sonnet 5.5 vs GPT-6 Sol: 5 of 5 each; Claude Sonnet 5.5 answered 1.3× sooner at the median and GPT-6 Sol cost 1.4× less. Claude Sonnet 5.5 vs GPT-6 Sol, on every job.

• Claude Sonnet 5.5 vs GPT-6 Luna: Claude Sonnet 5.5 5 of 5, GPT-6 Luna 4; Claude Sonnet 5.5 answered 1.3× sooner at the median and GPT-6 Luna cost 25.1× less.

• Claude Sonnet 5 vs GPT-6 Astra: 5 of 5 each; GPT-6 Astra answered 1.5× sooner at the median and Claude Sonnet 5 cost 2.6× less.

• Claude Sonnet 5 vs GPT-6 Sol: 5 of 5 each; GPT-6 Sol answered 1.8× sooner at the median and cost 1.8× less. Claude Sonnet 5 vs GPT-6 Sol, on every job.

• Claude Sonnet 5 vs GPT-6 Luna: Claude Sonnet 5 5 of 5, GPT-6 Luna 4; GPT-6 Luna answered 1.8× sooner at the median and cost 33.5× less.

• Claude Haiku 4.5 vs GPT-6 Astra: 5 of 5 each; Claude Haiku 4.5 answered 1.2× sooner at the median and cost 5.6× less.

• Claude Haiku 4.5 vs GPT-6 Sol: 5 of 5 each; they took about as long and Claude Haiku 4.5 cost 1.2× less. Claude Haiku 4.5 vs GPT-6 Sol, on every job.

• Claude Haiku 4.5 vs GPT-6 Luna: Claude Haiku 4.5 5 of 5, GPT-6 Luna 4; they took about as long and GPT-6 Luna cost 15.6× less. Claude Haiku 4.5 vs GPT-6 Luna, on every job.

Every Claude and GPT reply above was checked the same way as every other model's, by the rules published with the prompts: how the math prompts are scored, and each one in full.

• The lineups

  Claude: 5 models, Claude Fable 5.1, Claude Opus 5.5, Claude Sonnet 5.5, Claude Sonnet 5, and Claude Haiku 4.5. GPT: 3 models, GPT-6 Astra, GPT-6 Sol, and GPT-6 Luna.

• Price per message

  The least expensive Claude model is Claude Haiku 4.5 (250 messages a month on Pro); the least expensive GPT model is GPT-6 Luna (60 messages a day on Pro).

• Context window

  Claude goes up to 1M tokens (Claude Fable 5.1); GPT up to 1.05M tokens (GPT-6 Astra).

• Images and PDFs

  Every model here reads images. Every model here takes a PDF as a whole file.

• On the Free plan

  Free's one-time trial of 5 messages covers Claude Sonnet 5.5, Claude Sonnet 5, Claude Haiku 4.5, GPT-6 Sol, and GPT-6 Luna. Paid plans have every model, with messages every month.

In llmwise, a message to Claude or GPT goes to the model's maker, or through OpenRouter when llmwise can't reach the maker directly. The Privacy Policy has the details.